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While loop subshell problem

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# 1  
Old 10-15-2011
Question While loop subshell problem
Hi,

I have the below script

Code:
while true; do
       read -p "Please enter schema password: " -s -e pswd1
       echo
       read -p "Please retype schema password: " -s -e pswd2
       echo
       [ "X$pswd1" != "X$pswd2" ] && { echo -e "password mismatch.\n"; continue; }
       validateOraclePassword $pswd1
       [ $? -eq 0 ] && break
done

where "validateOraclePassword" is a function which checks if the password follow our database policy.

The above code is used by multiple components and so i'm trying to build a master script which calls all components in 1 go as below

Code:
/opt/component1.sh <<!
password
password
!
/opt/component2.sh <<!
password1
password1
!

My problem is that WHILE loop creates a subshell when it run and because of that the $pswd1 is empty when validateOraclePassword function is called.


Any idea how i can fix it?

Many thanks in advanced,

Dani
# 2  
Old 10-15-2011
Code:
while true; do
       read -p "Please enter schema password: " -s -e pswd1
       echo
       read -p "Please retype schema password: " -s -e pswd2
       echo
       if [ "X$pswd1" != "X$pswd2" ] || [ "X$pswd1" == "X" ]; then
           echo -e "password mismatch or password is empty.\n"; continue;
       else
          echo validateOraclePassword $pswd1
          [ $? -eq 0 ] && break
      fi
done

# 3  
Old 10-15-2011
MySQL
Quote:
Originally Posted by rdcwayx
Code:
while true; do
       read -p "Please enter schema password: " -s -e pswd1
       echo
       read -p "Please retype schema password: " -s -e pswd2
       echo
      if [ "X$pswd1" != "X$pswd2" ] || [ "X$pswd1" == "X" ]; then
          echo -e "password mismatch or password is empty.\n"; continue;
      else
echo validateOraclePassword $pswd1 > /dev/null
         [ $? -eq 0 ] && break
     fi
done

It does work with a minor change as i don't want to show the password in clear Smilie

Many thanks,
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