find greater than value


 
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# 8  
Old 10-12-2011
My output is in variable and i want to read that variable and print the required number.

The above solutions are perfectly working with outfile. But I dot want to create file to store values and process that.

This is what i am trying here.

Code:
dategrep()
{
 varlinenum=$1
 varSESSTRANS_CL="$(egrep -n "<\/SESSTRANSFORMATIONINST>" tmpsess9580.txt | cut -d":" -f1)"
 echo $varSESSTRANS_CL 
 echo $varSESSTRANS_CL | awk '{if($1>'$varlinenum'){print $1;exit}}'
}

dategrep 8

Output of the echo $varSESSTRANS_CL is..
Code:
5
7
10
13
18
21

Code:
echo $varSESSTRANS_CL | awk '{if($1>'$varlinenum'){print $1;exit}}'

this stmt is not working or not printing anything..

Last edited by radoulov; 10-12-2011 at 04:20 PM..
# 9  
Old 10-12-2011
Quote:
Originally Posted by tmalik79
My output is in variable and i want to read that variable and print the required number.

The above solutions are perfectly working with outfile. But I dot want to create file to store values and process that.

This is what i am trying here.

dategrep()
{
varlinenum=$1
varSESSTRANS_CL="$(egrep -n "<\/SESSTRANSFORMATIONINST>" tmpsess9580.txt | cut -d":" -f1)"
echo $varSESSTRANS_CL
echo $varSESSTRANS_CL | awk '{if($1>'$varlinenum'){print $1;exit}}'
}

dategrep 8

Output of the echo $varSESSTRANS_CL is..
5
7
10
13
18
21

Code:
echo $varSESSTRANS_CL | awk '{if($1>'$varlinenum'){print $1;exit}}'

this stmt is not working or not printing anything..
Code:
echo "$varSESSTRANS_CL" | awk '{if($1>'$varlinenum'){print $1;exit}}'

This User Gave Thanks to ygemici For This Post:
# 10  
Old 10-12-2011
Thank you very much.
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