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Problem in Diff command...

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# 1  
Old 10-12-2011
Problem in Diff command...
Hi All,

I havae 2 files like this
File1.dat.tar.gz--- has
Code:
+667866066123|20110506
+667866066866|20110405

File2.dat.tar.gz -----contains
Code:
+447866066123|20110505
+447866066866|20110405

If I give

Code:
Gzcat File1.dat.tar.gz | cut –d “|” –f 1 > out1.dat 
Gzcat File2.dat.tar.gz| cut –d “|” –f 1 > out2.dat

Now out.dat contains 3 rows
Code:
/users/sur/file1.dat 
+667866066123
+667866066866

Out2.dat contains 3 rows
Code:
File2.dat
+447866066123
+447866066866

Code:
Diff out1.dat out2.dat

Then it says
Code:
1c1
< /users/sures_p/file1.dat
---
File2.dat

It means the first line in those 2 files are the previous filenames.
Either I have to ignore the first line from the 2 files when doing diff.

Any help is really appreciated.
Last edited by Franklin52; 10-12-2011 at 04:14 AM.. Reason: Please use code tags, thank you
# 2  
Old 10-12-2011
Not sure if they are just typos, you did a diff between out1.dat and out2.dat. You have pasted the output of out.dat and Out2.dat

what is the issue here?

--ahamed
# 3  
Old 10-12-2011
Thanks for your reply ahamed.

In my two output files I am getting the source filenames in my target output files. Now, I need to load the data in target file without having source filenames. I tried a lot. But everytime I am getting source filename in my target output files.
out.dat
Code:
/users/sur/file1.dat 
+667866066123
+667866066866

Out2.dat
Code:
File2.dat
+447866066123
+447866066866

Original output should be
out.dat
Code:
+667866066123
+667866066866

Out2.dat
Code:
+447866066123
+447866066866

Last edited by Franklin52; 10-12-2011 at 06:36 AM.. Reason: Please use code tags, thank you
# 4  
Old 10-12-2011
Code:
gzcat File1.dat.tar.gz | cut –d “|” –f 1 | sed '1d' > out1.dat

--ahamed
# 5  
Old 10-12-2011
I resolved my problem. Thanks ahamed.
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