bash: delete a string from last line


 
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# 1  
Old 10-11-2011
bash: delete a string from last line

I am using a while loop to read a file and i have to delete a string from the last line. Here is the code so far:
1. Read line by line from file new.html using while loop and store in a variable data
2.Now, need to replace '||chr( from last line in data

I am able to replace that character from the last line of new.html, but still working on the variable data.
# 2  
Old 10-11-2011
Code:
data=$(echo $data | sed s/||chr(/new thing/)

# 3  
Old 10-11-2011
hi you must use sed fro this for simple waySmilie
Code:
sed -i '$s/chr/newchrr/' yourfile

read last line with
$s--> substitue "chr" to newchr in yourfile
-i --> edit(save) in place if you use gnu sed
or
Code:
sed '$s/chr/newchrr/' yourfile > tmpfile && mv tmpfile yourfile

regards
ygemici
# 4  
Old 10-11-2011
@Skrynesaver:
I used
data=$(echo $data | sed s/||chr(//) -- to replace the string with empty space
and i got the following error (also tried a couple of different ways)
unexpected EOF while looking for matching `)'

I think my text was misleading - i have to replace the string '||chr( with an empty space and this has to be done only for the last line in the variable data got from the loop.
# 5  
Old 10-11-2011
Code:
data=$(echo $data | sed 's/||chr(//')

# 6  
Old 10-11-2011
@ygemici:

thank you for your reply, as I have already mentioned I am able to do with the file say new.html (your file). But I am not yet able to achieve it for a variable got from the while loop.
If you have a similar solution for variable instead of filename, that will be really helpful.

I tried things like below to replace the string with empty which did not work. Basically i wanted to remove that string from the last line
sed '$s/'\''||chr(9)||/ /g' data > tmpfile.txt
sed '$s/'\''||chr(9)||/ /g' $data > tmpfile.txt
sed '$s/'\''||chr(9)||/ /g' ${data} > tmpfile.txt
# 7  
Old 10-11-2011
If you want to use variables for file names:
Code:
mInp='MyInpFile'
mOut='MyOutFile'
sed '$s/.||chr(9)||//' ${mInp} > ${mOut}

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