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Return part of string after X numbers of a character

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# 1  
Old 10-10-2011
Return part of string after X numbers of a character
My input strings look something like this:
Code:
/dev/vs/dsk/group/vol

I want to print just "group" out of the line... which is always found between the 4th and 5th "/" in the string.

I figure I have to use awk, sed, or some combination to do this, but I've searched the forums and can't find anything matching what I need to do. Smilie

Can anyone please help me do this in ksh?
Last edited by radoulov; 10-10-2011 at 10:42 AM.. Reason: Code tags.
# 2  
Old 10-10-2011
This could be done:

1. In pure shell (using parameter expansion):

Code:
% s=/dev/vs/dsk/group/vol   
% ss=${s#/*/*/*/*} ss=${ss%/*}
% echo "$ss"                  
group

2. Using an external command (if you find it more readable or if you need to replace the 50th occurrence Smilie):

Code:
ss=$(
  printf %s "$s" |
    cut -d/ -f5
  )

or (if your shell supports here strings - ksh93 supports them, ksh88 doesn't)

Code:
ss=$(
  cut -d/ -f5 <<< "$s"
  )

Last edited by radoulov; 10-10-2011 at 10:57 AM..
# 3  
Old 10-10-2011
THANK YOU! I would've never figured that one out!
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