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Shell Programming and Scripting

Color line based on first field

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# 1  
Old 10-03-2011
Color line based on first field
Hello,

I have a bash script that outputs the following text to a file and then prints that file to the screen:

Code:
|64     |30     |0      |8      |23:59:14
|38     |57     |2      |14     |00:09:05
|29     |50     |4      |20     |23:58:04
|20     |48     |7      |23     |00:05:44
|18     |33     |5      |22     |00:00:35
|14     |18     |8      |31     |00:53:19
|11     |36     |4      |19     |23:27:06
|8      |30     |7      |30     |23:59:22
|6      |8      |3      |11     |00:14:18
|4      |15     |7      |28     |23:48:20
|4      |14     |6      |20     |23:47:29

I would like to color each entire line of this file based on the first field being less than or greater than 60. Anyone have any tips to complete this?
# 2  
Old 10-03-2011
assume that your result are located in FILENAME , run this :
Code:
IFS=$old_IFS
IFS=$'\n'
for line in $(cat FILENAME);do
if [ `echo $line |awk -F"|" '{print $2}'` -gt 60 ];then
    echo -e "\033[31m${line}\033[0m" 
else
    echo $line
fi
done
old_IFS=$IFS

# 3  
Old 10-03-2011
Code:
$ awk -F\| '{if ($2>60) {print "echo \"\033[31m"$0"\033[0m\""}}' infile | sh
|64     |30     |0      |8      |23:59:14

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