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# 1  
Old 02-14-2005
echo problem

Hi,

I have given the following statement in a script to put the values of variables (VAR1, VAR2,...) in a file.

echo " $VAR1 $VAR2 $VAR3 $VAR4 $VAR5" >> filename

But the output is not coming properly. Variables VAR5, VAR4 are replacing the first (VAR1, VAR2,..). I can't figureout the reason. Say

VAR1=50; VAR2=51; VAR3=52; VAR4=53; VAR5=54;

Output: 53 54 52 (Something like this)

But if you echo each variable separately it is echoing properly.

Can anyone help me on this ?

Thanks
Ben
# 2  
Old 02-14-2005
Hi,

Your scripts works fine, didn't encounter the problem u mentioned. Not sure why u have such problem. I just test out these two sentences. Look at your syntax again. u must have put the variable in echo at the wrong order.

VAR1=50; VAR2=51; VAR3=52; VAR4=53; VAR5=54;

echo " $VAR1 $VAR2 $VAR3 $VAR4 $VAR5" >> testtest
# 3  
Old 02-14-2005
If we assign values then it would work fine.

But if we get values from files & then echo them there'll be problem.

Ben
# 4  
Old 02-14-2005
hello..

For me ..its working fine...even assigning values during execution..
please check the code once more. there might me some other problems

regards
esham
# 5  
Old 02-14-2005
try putting tabs in between the varaibles

Code:
echo " $VAR1\t $VAR2\t $VAR3\t $VAR4\t $VAR5\t" >> filename

# 6  
Old 02-14-2005
Quote:
Originally Posted by bhargav
try putting tabs in between the varaibles
Just a note that some versions of echo (notably Linux) require the "-e" option to enable interpretation of backslash-escaped sequences, e.g.

echo -e "blah\tblah\tblah"

Cheers
ZB

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