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Shell Script : Need Help

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# 1  
Old 09-22-2011
Shell Script : Need Help
I've a file Test.log. The contents of the file is as follows :

Code:
sdadadasdsa
***--aaaaaaaaaaaaaaa
kjsdfjdsakfjskfjasd
***--sdfasdfasfsdf
***--fdsfbfgbhgh
dfgvfgbgbbg

I want to run a script that should delete all the lines that doesnot start with '***--'

I ran the below script :

Code:
nawk 'match($0,"***--") != 0 {print $0}' Prcs_Schdlr_Check.log > Result.log

It is giving the below message :

Code:
nawk: illegal primary in regular expression ***-- at **--
source line number 1
context is
>>> match($0,"***--") <<<

Could some one please tell me what am doing wrong?
I'm running the script on SunOS 5.10
Moderator's Comments:
Mod Comment
Please use code tags when posting data and code samples!
Last edited by vgersh99; 09-22-2011 at 12:49 PM.. Reason: code tags, please!
# 2  
Old 09-22-2011
Code:
sed '/^***--/d' Prcs_Schdlr_Check.log > Result.log
OR
nawk '!/^\*\*\*--/' Prcs_Schdlr_Check.log > Result.log

# 3  
Old 09-22-2011
Hi vgersh99,

Thanks a lot for your quick response.

The code that you gave is deleting all the lines that start with '***--'

But I wanted it in the other way. It should delete all the lines except those starting with '***--'. In other words, the output should have only the lines starting with '***--'

Regards,
Pandee
# 4  
Old 09-22-2011
sorry:
Code:
nawk '/^\*\*\*--/' myFile
sed -n '/^***--/p' myFile

# 5  
Old 09-22-2011
Code:
sed -n '/^***--/p' yourfile

# 6  
Old 09-22-2011
It worked !!!
Thanks a lot guys for your lightening quick responses... Smilie
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