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Using AWK how its possible??

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Top Forums Shell Programming and Scripting Using AWK how its possible??
# 8  
Old 09-22-2011
Mine worked fine. Did you not try it?

Code:
[mute@geek ~/asia]$ awk '(i=match($1,/[^.]+\.asia/))&&(d=tolower(substr($1,i,RLENGTH)))&&!a[d]++{print d;tot++}END{print "Total",tot,"Domains"}' zone

0008.asia
anish.asia
Total 2 Domains

Last edited by neutronscott; 09-22-2011 at 03:48 PM.. Reason: escape '.'
# 9  
Old 09-22-2011
Quote:
Originally Posted by neutronscott
Mine worked fine. Did you not try it?

Code:
[mute@geek ~/asia]$ awk '(i=match($1,/[^.]+\.asia/))&&(d=tolower(substr($1,i,RLENGTH)))&&!a[d]++{print d;tot++}END{print "Total",tot,"Domains"}' zone

0008.asia
anish.asia
Total 2 Domains


its works but here i posted sample zone file only dude..sorry that was my mistake only..

suppose in my zone file this means your code wont woks na?

Quote:
0008.ASIA. NS AS2.DNS.ASIA.CN.
0008.ASIA. NS AS2.DNS.ASIA.CN.
ns1.0008.asia. NS AS2.DNS.ASIA.CN.
www.0008.asia. NS AS2.DNS.ASIA.CN.
anish.asia. NS AS2.DNS.ASIA.CN.
ns2.anish.asia NS AS2.DNS.ASIA.CN
ANISH.ASIA. NS AS2.DNS.ASIA.CN.
neutronscott.ASIA NS AS2.DNS.ASIA.CN.
that time
but using this camel case format it works thanks alot..man for your help

Code:
awk '(i=match($1,/[^.]+\.[Aa][Ss][Ii][Aa]/))&&(d=tolower(substr($1,i,RLENGTH)))&&!a[d]++{print d;tot++}END{print "Total",tot,"Domains"}' filename

# 10  
Old 09-22-2011
How about this:

Code:
awk -F'[. ]' 'tolower($3)=="asia" {$1=$2;$2=$3} NF>3&&$2=="asia"&&!_[tolower($1)]++{print $1"."$2}
END{print "Total",length(_),"Domains"}' file1

# 11  
Old 09-22-2011
Quote:
Originally Posted by Chubler_XL
How about this:

Code:
awk -F'[. ]' 'tolower($3)=="asia" {$1=$2;$2=$3} NF>3&&$2=="asia"&&!_[tolower($1)]++{print $1"."$2}
END{print "Total",length(_),"Domains"}' file1


it works only the tlds are lowercase.. suppose if a zone file contains

Quote:
Chubler.ASIA. NS AS2.DNS.ASIA.CN.
this kind of data mean your code wont show this data in count :-(
# 12  
Old 09-22-2011
Quote:
Originally Posted by anishkumarv
but using this camel case format it works thanks alot..man for your help

Code:
awk '(i=match($1,/[^.]+\.[Aa][Ss][Ii][Aa]/))&&(d=tolower(substr($1,i,RLENGTH)))&&!a[d]++{print d;tot++}END{print "Total",tot,"Domains"}' filename

Oh. My folly. I see now the problem. That is a good solution, or like you had before with gawk's IGNORECASE=1.

Code:
gawk '...' IGNORECASE=1 file

or move the tolower() to be first

Code:
awk '(d=tolower($1))&&(i=match(d,/[^.]+\.asia/))&&(d=substr(d,i,RLENGTH))&&!a[d]++{print d;tot++}END{print "Total",tot,"Domains"}' zone

Many ways...

---------- Post updated at 04:18 PM ---------- Previous update was at 03:57 PM ----------

I found 'scott.asia.asia' would not match correctly. I re-write it to be generic, in that "asia" is not even apart of the code.. this will work best, i think, in the future.

Code:
[mute@geek ~/asia]$ cat scr
#!/usr/bin/awk -f
$1 ~ /^[^;@$]+.+\..+/{d=tolower($1);gsub(/\.$/,"",d);n=split(d,a,".");d=a[n-1]"."a[n];if(!_[d]++){tot++;print d}}
END{print "Total",tot,"Domains"}
[mute@geek ~/asia]$ ./scr zone
0008.asia
anish.asia
asia.asia
Total 3 Domains
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