Shell Programming and Scripting

I have a report file which somewhere has a lines starting with word ".sub"

I have a new variable named $new.
What i am trying to do is insert the content of $new just before the occurrence of ".sub" in the report file.

How can I do that?

Code:

sed "s/^.sub/$new.sub/" file > newfile

Hey, Franklin thanks..
actually I needed the $new so be printed a line before occurence of .subckt

earlier file

Code:

a
b
c
.sub efgh

new file

Code:

a
b
c
$new.sub
.sub efgh

Hi,
please find the below code, hope this might work for your need.
but this will insert the content of $new just before the coourance of ".sub" in the report file for all the lines which are starting with ".sub" only.

Code:

 
 sed -i "s/^.sub/$new.sub/g" report_file

if you want to insert everywhere in file where ever the string occurs,
you can use the below code:

Code:

 
sed -i "s/.sub/$new.sub/g" report_file

Hope you got these....

Code:

awk -v var=$new '/^.sub/{print var ".sub"}1' file > newfile

hey thanks..
it works

Hey Guys, I am trying to add a new requirement to the query above..
I will explain it with an example:

Original String

Code:

a
b
c
.sub efgh
d
e
.sub fgh

Edited String : The New line is added only before the line with first .sub statement. Hence even if .sub statement occurs for 100 times, the new line "$new" will be added only before the first .sub statement.

Code:

a
b
c
$new.sub
.sub efgh
d
e
.sub fgh

Hence.. the requirement is: how can I make the awk statement (as given by Franklin) exit after the occurrence of first .sub statement.