Shell Programming and Scripting

Hi everyone !

suppose i'm searching for a specific string in a file so it is very easy, i use the following command

Code:

grep 'keyword' file_name

but how to search a word which is repeated maximum number of times in a file, for example in the following text i have to search a word which is repeated maximum number of times and that is john

""Hi John, how are you John, where have you been John, John is 14 years old""

what kind of technique do i have to use? is there any built in functions

Try:

Code:

perl -ln0e 'while (/\w+/g){$a{$&}++}@x=sort {$a{$b}<=>$a{$a}} keys %a;print $x[0]' file_name

Do you mean count the words? or do you mean find John? or both?

Code:

awk '{ for (i=1;i<=NF;i++) {arr[$i]++}  }  END{ for(i in arr){print arr[i], i }} ' inputfile |
      sort -n > outputfile

output file has word counts, you can play with that. i.e.,

Code:

grep John outputfile

another funny idea:

Code:

 convert ", . ? !" to " "
 convert " " -> "\n"
then:
sort|uniq -c|sort|tail -n 1

Hi thanks but i guess you didn't understand my point

i want to search the code to find the word that is repeated maximum number of times.

for example i ask my program to find a word that is repeated maximum number of times and it bring the word that is repeated highest number of times.

---------- Post updated at 01:22 AM ---------- Previous update was at 01:13 AM ----------

Hey jim !

your code is very close to what i asked for but it has some problem it has printed "John" twice i don't know why

output file:

1 14
1 are
1 been
1 have
1 Hi
1 how
1 is
1 John
1 old
1 where
1 years
2 you
3 John

and it will be good if it only save the word which is repeated maximum number of times... thanks anyways

i'm trying on the code if i fixed it i'll post here if anyone else need it

Code:

$nawk -F"[,.?\! ]" '{ for (i=1;i<=NF;i++) {arr[$i]++}  }  END{ for(i in arr){print arr[i], i }} ' input | sort -nr

it works fine... thanks everyone

hats off to itkamaraj