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Shell script wont execute

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# 1  
Old 09-09-2011
Question Shell script wont execute
Im using a script that writes a random line to a text file then executes another shell script. My problem is that the lottery shell script will not execute. Im not receiving an errors when running the shell script, and it copies a random line of text to mtest.txt fine.

Code:
#!/bin/bash

nscripts=2
rn=$(( ($RANDOM % $nscripts)+1 ))

case $rn in
    1) echo 'test1' >> mtest.txt;;
    2) echo 'test2' >> mtest.txt;;
esac

msg=`printf "./lottery.sh\r"`
exit

# 2  
Old 09-09-2011
Yes, of course. Because you don't run this script you just assign its name to variable "msg". And you don't use it and use unnecessary exit command.
Learn to use -x option and understand the output:
Code:
bash -x your_script

And do not try to write some fancy scripts before you get to work simpler ones.
# 3  
Old 09-09-2011
Quote:
Originally Posted by kylecn
My problem is that the lottery shell script will not execute.

Because you are not executing it. You are just assigning the output of printf to the variable "msg". ./lottery.sh snippet would do that.
# 4  
Old 09-09-2011
Well that makes sense. Im very new to shell scripting, and it doesn't help that i keep leaving and coming back to it.

Things are working appropriately now, back to messing around with different options Smilie thank you
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