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Unix Shell basic loop massive n00b

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# 15  
Old 09-01-2011
Put a space after the 3 here: if [ "${#cSID}" -ne 3]

To assign last element of line to end of array:
Code:
my_array[${#my_array[@]}]=$(sed -n "s/^$cSID.*://p" users.db)

Last edited by Chubler_XL; 09-01-2011 at 07:59 PM.. Reason: Missed users.db
# 16  
Old 09-01-2011
Quote:
Originally Posted by Chubler_XL
Put a space after the 3 here: if [ "${#cSID}" -ne 3]

To assign last element of line to end of array:
Code:
my_array[${#my_array[@]}]=$(sed -n 's/^$cSID.*://p users.db
')


Thank you!

although i got a bit confused with the array thing given that i got an array of 6 inputs
if this
Code:
my_array[${#my_array[@]}]=$(sed -n 's/^$cSID.*://p users.db
')

[/QUOTE]
is the last element
how do i select the other 5 ?

thx
# 17  
Old 09-01-2011
Oh sorry, I missunderstood your request - to load the line for cSID into an array you could use:

Code:
IFS=: my_array=( $(grep "^$cSID" users.db) )

Example:
Code:
$ cat users.db
423:name:surname:18:14:5
666:Ferris:Lucy:15:6:17
069:Chong:Annabel:15:20:16
987:Marple:Mike:13:19:12  
 
$ cSID=069
 
$ IFS=: my_array=( $(grep "^$cSID" users.db) )
 
$ echo Items=${#my_array[@]}  3rd=${my_array[2]}
Items=6 3rd=Annabel
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