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Wget exit code for each line in file

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# 1  
Old 08-30-2011
Wget exit code for each line in file
I am trying to validate links inside file if its up or not.

Heres what I am trying :


Code:
#!/bin/bash
link='cat url'
get=$(wget -q "$link") 
if [ "$get" -ne 0 ]
  then echo "Link not up"
  else echo "OK"
fi


Code:
$ ./validate
./validate: line 4: [: : integer expression expected
OK
$

Please suggest ..

Thanks,
Sriram
Last edited by radoulov; 08-30-2011 at 05:21 AM.. Reason: Use code tags, please!
# 2  
Old 08-30-2011
wget -q returns nothing to STDOUT...
You probably want to check it's return value:
Code:
while read url; do
  wget -q "$url"
  if [ $? -ne 0 ]; then
    echo "Link not up"
  else
    echo "OK"
  fi
done < url

# 3  
Old 08-30-2011
Thanks a ton sulti ....
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