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Listing files in a particular format

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# 1  
Old 08-23-2011
Listing files in a particular format
Hi,

My unix version is as follows:

Code:
uame -a

HP-UX server-name B.11.11 U 9000/800 2329770924 unlimited-user license

I just want to get file listing is a particular format listed below.

Code:
name  permission set(octal)  size  date (mon dd, yyyy)

I am trying to use the following command.

Code:
ll | egrep -v '^d' | awk '{ printf "%-29s\t\t%s\t%5s\t\t%s %s,%s\n", $9,$1,$5,$6,$7,$8 }'

But its giving me output like follows-

Code:
a.out                                   -rw-------          0           Aug 5,06:55

While the required output is

Code:
a.out                                   600          0           Aug 5, 2011

Also its giving me a 'total' line in the beginning while using above given command. I also don't want that line in my output.

Please help me achieve output in desired format.

Many thanks,
Manu
# 2  
Old 08-23-2011
Code:
ll | awk ' !/^d/ { if(NR>1) {printf "%-29s\t\t%s\t%5s\t\t%s %s,%s\n", $9,$1,$5,$6,$7,$8} }'

better to post your ls command output and the required output format
This User Gave Thanks to itkamaraj For This Post:
manubatham20
# 3  
Old 08-23-2011
Thanks.

Your code removed the first line, where total blocks are written.

Please also help me achieving file creation date in mon dd, yyyy format instead of mon dd hh:mm format.

Thanks.
# 4  
Old 08-23-2011
A clue to get the year!,

if the file is created on the current year, then the file timestamp will be shown in hh:mm format.

So, try something like this:

Code:
 
ls -l | awk '{$(NF-1)=$(NF-1)~/:/?"2011":$(NF-1);print}'

You have to add the above code in your requirement.
# 5  
Old 08-23-2011
Hi Panyam,

Thanks for your consideration.

But it's not always true, that if file is created only in the current year, then only time will be show.

Consider the case that today is "2nd Jan 2011", and file is created on "29th Dec 2010". Year has been changed since the time of file creation (2010 to 2011). But still it will show the date in dd mon hh:mm (29 Dec 3:54) format. Kindly consider this case as well.

Regards,
Manu
# 6  
Old 08-23-2011
Manu,

If you post the ls command output and the required output format, then you can get answers soon.

Always give the clear input and output format. Smilie
# 7  
Old 08-23-2011
Hello,

I'm sorry I did not read it fully. Indeed, it's not creation time but modified time.

man ls , gives

Code:
 
If the time of last modification is greater than six months ago, or any time in the future, the year is substituted for the hour and minute of the modification time.

So, need to find a logic here to get the years!!!.
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