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Replacing Complex Characters in vi

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# 1  
Old 08-20-2011
Replacing Complex Characters in vi
ok, so i have a number of commands like the below in a script:


Code:
/usr/bin/awk "/[#|^


I need to replace the bolded with "^\[\#\| but i'm having tremendous difficulties accomplishing this. This needs to be done in vi.

can someone please help me out?
# 2  
Old 08-20-2011
Code:
0,$ s/\/\[\#|\^/\^\\\[\\\#\\\|/g

# 3  
Old 08-20-2011
Code:
:%s/[[|#]/\\&/g

# 4  
Old 08-20-2011
Quote:
Originally Posted by yazu
Code:
:%s/[[|#]/\\&/g



this seems to work but it changes other characters it isn't meant to change.

basically,

i want to replace "/[#|^ with exactly "^\[\#\|
# 5  
Old 08-21-2011
Quote:
Originally Posted by SkySmart
this seems to work but it changes other characters it isn't meant to change.

basically,

i want to replace "/[#|^ with exactly "^\[\#\|
It is all about what gets escaped and what doesn't.
(") doesn't get escaped
(/) it does get escaped (\/)
([) it does get escaped (\[)
(#) doesn't get escaped
(|) doesn't get escaped
(^) it does get escaped (\^)
(\) it does get escaped (\\)

I bet you can conjure a proper syntax that will match what you want.
Code:
:% s/"\/\[#|\^/"\^\\\[\\#\\|/g

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