Shell Programming and Scripting

Hi,

I need to find the word with numbers (alpha-num) like XYZ1234.
But the file has some **Result of XYZ1234** strings,which i dont want to take or omit.
how can search string and not that particular string?
after reading it to array,i searched

foreach $find(@array)
{
if ($find=~ m/string(\d+))
{
print $find
}
}

Thanks in Advance

please provide the input format and output format

so, if the file has the below string

Code:

 
Result of XYZ1234

then you need the output as XYZ1234 only ?

Hi itkamaraj,

I have some html file it contains table.In that i need to find string like "details" and print below lines which have XYZ1234.
But in file,some string "Results of XYZ1234" also which i don't want to take.

Thank You for reply

still, u didnt give sample input file and output file

In the find command use without use "!" option or "-not" option not to search for a particular string.

For example:
find . -name "*".pl -not -name "*".sh -type f

will list all the files ending with ".pl" and exlude all the files ending with ".sh"

For more understanding refer to the blog:
http://linux-forum-karthik.blogspot....name-and.html:)

Code:

 
$ nawk ' /[A-Z][0-9]/ && ! /Results/ {print $0}' test
details XYZ1234
details XYZ1234
details XYZ1234
details XYZ1234

 
$ cat test
details XYZ1234
Results of XYZ1234
Results of XYZ1234
details XYZ1234
details XYZ1234
details XYZ1234
Results of XYZ1234

Hi,

i have attached input and output file for your reference.