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Shell Programming and Scripting

command not found error

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# 1  
Old 07-24-2011
command not found error
hello

every time i run the following code


Code:
for val in fileX fileY fileZ
do
$val=`ls -l $val | awk '{print $5}'`
done

i got error message command not found , i tried to add ' and " but nothing works

its only worked wen remove $val=

but i want the name of the file and the value

thanks to advice
Last edited by radoulov; 07-25-2011 at 08:58 AM.. Reason: Code tags, please!
# 2  
Old 07-24-2011
I think what you want is something like this:

Code:
info="$val $(ls -l $val | awk '{print $5}')"

which will assign the current file name and then the file size into the variable info.
# 3  
Old 07-24-2011
Do as a favor and post what you are trying to accomplish.
The example lines are broken at many levels and figuring out what you are trying to do is not productive.

In any case, to answer your question. $val=`ls -l $val | awk '{print $5}'`

Remove the dereferencing $ in red.
# 4  
Old 07-25-2011
Quote:
Originally Posted by agama
I think what you want is something like this:

Code:
info="$val $(ls -l $val | awk '{print $5}')"

which will assign the current file name and then the file size into the variable info.
hello

i want the out put like this

fileX=54831 (the number is the file size)
fileY=75778
fileZ=457455

---------- Post updated at 01:22 AM ---------- Previous update was at 01:22 AM ----------

Quote:
Originally Posted by Aia
Do as a favor and post what you are trying to accomplish.
The example lines are broken at many levels and figuring out what you are trying to do is not productive.

In any case, to answer your question. $val=`ls -l $val | awk '{print $5}'`

Remove the dereferencing $ in red.
hello

i want the out put like this

fileX=54831 (the number is the file size)
fileY=75778
fileZ=457455
# 5  
Old 07-25-2011
Try:
Code:
for val in fileX fileY fileZ
do
  size=`ls -l val | awk '{print $5}'`
  echo "$val=$size"
done

# 6  
Old 07-25-2011
Quote:
Originally Posted by mogabr
hello

i want the out put like this

fileX=54831 (the number is the file size)
fileY=75778
fileZ=457455

---------- Post updated at 01:22 AM ---------- Previous update was at 01:22 AM ----------



hello

i want the out put like this

fileX=54831 (the number is the file size)
fileY=75778
fileZ=457455
Code:
# for val in fileX fileY fileZ; do echo $val=$(stat -c %s $val) ; done

Code:
# for val in fileX fileY fileZ; do echo $val=`ls -l $val|awk '{print $5}'`; done

# 7  
Old 07-25-2011
If you prefer awk then..
Code:
ls -l file? | awk '{print $NF"="$5}'
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