Shell Programming and Scripting

Hey guys!

This should be fairly easy to most, not me evidently!

I've written a script (see below). This script is going to be run daily, on a Task Scheduler, as data is going to be continuously added to the files it reads from(all the .dat files in the '2011' folder).

Basically, whenever the script is run, instead of writing over the old file, it just adds to it, so I have the exact same data over and over again, plus bits of new data.

Is there any way of writing over the old file each time the script is run?

Help is very much appreciated

Code:

#!/bin/bash

# input files from each day of data and combine into one big file
find /u/Picarro/DataLog/2011 -type f -name "*dat" -exec cat {} >> data.dat \;

#use new combined data as input file
IN_all='/u/Picarro/DataLog/2011/data.dat' 
	
# the csv file to create for all data called 'data.csv' in the respective directory
OUT_all='/u/Picarro/DataLog/2011/Awk/data.csv'		

# gawk files to create csv file
GAWK='/u/Picarro/DataLog/2011/Awk/Format_trial.csv.awk'

#produce the OUT file from the IN file(s)
$GAWK $IN_all >> $OUT_all

Instead of using ">>" try just using ">"
">>" adds to the file while ">" will overwrite.