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How to display a counter in shell script?

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# 8  
Old 07-08-2011
Just use printf and you won't have to worry about whether your echo supports -e \r -- all printf supports \r. You can also specify %3d to keep the number nicely aligned.

Code:
printf "\r%3d %s" $cnt $file

# 9  
Old 07-09-2011
Hi,
Thank you kshji for your help. Your code gave me the correct logic.. Now the below code works perfectly.. Smilie

Code:
cnt=0                                 
bal=`ls -lrt *.txt |wc -l`                                              
for file in *.txt                           
do                    
     cnt=$((cnt+1))
     bal=$((bal-1))
     echo  "\rProcessed Files :: $cnt Remaining ::$bal\c"                    
     $EXEC/xxx.exe $file      >>$HOME/file_process.log                             
done
echo 
echo "Processing completed"

One word to pludi
" I tried your code and didn't work. Thanks."

Thanks to all replied.
Jaise
# 10  
Old 07-09-2011
Quote:
Originally Posted by jaiseaugustine
One word to pludi
" I tried your code and didn't work. Thanks."
Pludi's code works fine under bash while I guess you are running ksh which doesn't implement a sub second sleep builtin.

I would slightly modify two lines of your script:
Code:
bal=`ls -lrt *.txt |wc -l`

"-lrt" is unnecessary as you only count the number of files anyway:
Code:
bal=$(ls *.txt |wc -l)

Code:
echo  "\rProcessed Files :: $cnt Remaining ::$bal\c"

As already advised, better to use printf which is standard and portable instead of implementation specific echo oddities:
Code:
printf "\rProcessed Files :: %4d Remaining ::%4d " $cnt $bal

This User Gave Thanks to jlliagre For This Post:
jaiseaugustine
# 11  
Old 07-13-2011
Hi,
I was trying in ksh. May be thats why it didnt work for me..
thanks to all replied...Smilie

Regards.
Jaise
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