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How to print only word with "_" or @ of a file?

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# 1  
Old 07-06-2011
How to print only word with "_" or @ of a file?
Hello all,

I have a text file but I need to have only words with string "_" or "@"

Code:
Before

text LD_ titi
blbla blabla name@domain lalala
titi name2@domain2 toto

Code:
After

LD_ titi
name@domain
name2@domain2

How can I do to do with linux? thanks in advance!
# 2  
Old 07-06-2011
"titi" is expected ???

Code:
xargs -n1 <yourfile | egrep -e '_|@'

---------- Post updated at 05:48 PM ---------- Previous update was at 05:44 PM ----------
Last edited by ctsgnb; 07-06-2011 at 01:06 PM..
# 3  
Old 07-06-2011
Code:
grep -Eo '([^ ]*@[^ ]*)|([^ ]*_[^ ]*)' file

# 4  
Old 07-06-2011
Try this,
Quote:
for i in `cat r`; do echo $i | egrep "@|_"; done
# 5  
Old 07-06-2011
Thank you Ctsgnb but xargs don't work to the end of the file, I got this error:
Code:
xargs: unmatched single quote; by default quotes are special to xargs unless you use the -0 option

And the sed command don't show the whole pattern Smilie
Code:
sed 's/[^ @_][^ @_]*//g;s/  */ /g;s/^ //;s/ $//'

---------- Post updated at 11:03 AM ---------- Previous update was at 10:56 AM ----------

Quote:
Originally Posted by Rksiva
Hi Rkisiva,
I can't run this command, can you explain how to use it please?
# 6  
Old 07-06-2011
Try execute like below,

Code:
for i in `cat <Input Filename>`
do
echo $i | egrep "@|_"
done

This User Gave Thanks to Rksiva For This Post:
benitto
# 7  
Old 07-06-2011
for me it works :
You right, the sed statement is erroneous i fixed my post.

Code:
# xargs -n1 <tst | egrep -e '_|@'
LD_
name@domain
name2@domain2

This User Gave Thanks to ctsgnb For This Post:
benitto
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