Shell Programming and Scripting

The xml file contains,
<?xml version="1.0" encoding="UTF-16"?>

here the code should search for this UTF-16 keyword and if found then need to convert the encoding to UTF-8 and then i want to replace this UTF-16 keyword to UTF-8.
Please help.

grep command is working for me

Code:

 
 
$ grep "UTF\-16" test.xml
<?xml version="1.0" encoding="UTF-16"?>

Did you change the agrs to args ? ( the typo in the last post )

Code:

 
for i in `find . -type f | xargs grep -l "UTF\-16"`
do
iconv -f UTF-16 -t UTF-8 $i > $i.old
sed 's/UTF-16/UTF-8/g' $i.old > $i
rm -f $i.old
done

Hi,

but grep "UTF\-16" filename
is not fetching any result for me if i try on the xml extension files.

If i try with sed -n '/UTF-16/p' filename it is working for individual file but for a number of files this command is not working.

you can use

are you using solaris ?

Code:

 
$ /usr/xpg4/bin/grep "UTF.16" test.xml
<?xml version="1.0" encoding="UTF-16"?>

Perhaps the backslash before the dash is the problem. Since the dash is not in any way special outside of a bracket range expression, technically that's an undefined sequence. Posix basic and extended regular expression implementations are allowed to behave differently when such a sequence is encountered. The implementation may throw a syntax error, discard the backslash and match the dash, match a literal backslash followed by a dash, or ask your cpu to self-destruct. It's best not to escape characters which are not special.

In the posix extended regular expression flavor, there are no ordinary characters which may be portably preceded by a backslash. In the posix basic regular expression flavor, there are only a few exceptions and dash outside of a bracket expression is not one of them: (, ), {, }, digits 1 through 9, and anything inside a bracketed expression.

For more info, see section 9.3.2 and 9.4.2 @ Regular Expressions

Regards,
Alister