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Calculating 7 days ago date for the given Argument

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# 8  
Old 07-01-2011
Hmmm. That's weird. It works fine here, pasted keystroke for keystroke, and I've not encountered a version of GNU date before that didn't have it. You definitely have a working -d option, since the epoch time it printed is correct for that date.

What does date --version show you? I've got 8.5.

Maybe it just doesn't have @ for epoch seconds? That can be worked around using the syntax tukuyomi noticed. Does date -d '20110701 - 7 days' work?
This User Gave Thanks to Corona688 For This Post:
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# 9  
Old 07-01-2011
Hi,

I have tested the below script in a different box and the version of date is :

Code:
$ date --version
date (GNU coreutils) 5.97
Copyright (C) 2006 Free Software Foundation, Inc.
This is free software.  You may redistribute copies of it under the terms of
the GNU General Public License <http://www.gnu.org/licenses/gpl.html>.
There is NO WARRANTY, to the extent permitted by law.


Perfect this is working now:

Code:
#!/bin/sh
Day=`date -d '20110701 - 7 days' +%Y%m%d`
echo $Day

Code:
 ./date.sh
20110624

But,

When I am trying to execute the same script in a different box:

Code:
$ date --version
date (coreutils) 4.5.3
Written by David MacKenzie.

Copyright (C) 2002 Free Software Foundation, Inc.
This is free software; see the source for copying conditions.  There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.

Result:
Code:
$ ./date.sh
20110708

Not sure why this is happening but wanted to know.

Really appreciate your quick responses and Thank you very much.
Last edited by rbatte1; 07-05-2016 at 04:57 AM.. Reason: Code tags
# 10  
Old 07-02-2011
That version of GNU date is 9 years out of date.
# 11  
Old 07-02-2011
try this..
Code:
$ date +%Y%m%d
20110702
$ TZ=CST+144 date +%Y%m%d
20110626
$
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