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User idle time and kill

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# 1  
Old 06-28-2011
User idle time and kill
Hello..

I have many sleepy users on my Solaris box and need to kill them if they are idle for more than 45 minutes for example...I know who -u gives and the idle time but unable to make a awk line to get the condition perfect. Please help...Smilie
# 2  
Old 06-28-2011
post the who -u output ( atleast two lines) and which column you are interested in ?
This User Gave Thanks to itkamaraj For This Post:
wimaxpole
# 3  
Old 06-28-2011
the below line will retain only the present day tty sessions.. else if you need to retain only <45 mins sessions, let us know.

Code:
$ who -u | grep -v "`date +%b" "%d`" | awk ' { print "kill -9 "$7 } ' | sh

This User Gave Thanks to jayan_jay For This Post:
wimaxpole
# 4  
Old 06-28-2011
Thanks for your replies...

Code:
test1      pts/2        Jun 28 11:10  0:21  14041     
test2      pts/3        Jun 28 11:10  0:20  14055       
test3      pts/4        Jun 28 11:11  0:20  14073      
root       pts/5        Jun 28 11:11   .    14092

In the above, filed #6 shows users are idling 0:21 and 0:20 minutes, I need to kill them if the go above 45 minutes but except root user. Thanks...
Last edited by Franklin52; 06-28-2011 at 07:39 AM.. Reason: Please use code tags for code and data samples, thank you
# 5  
Old 06-28-2011
Code:
 
for in in `who -u | nawk ' ! /^root/ { if(substr($6,length($6)-1,length($6)) > 20) printf ("%s ",$1) }'`
do
 #kill here
done

This User Gave Thanks to itkamaraj For This Post:
wimaxpole
# 6  
Old 06-28-2011
Thanks very much.. wonder full script.
# 7  
Old 06-28-2011
you need to change the condition

Code:
 
 > 20  to > 45

This User Gave Thanks to itkamaraj For This Post:
wimaxpole
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