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# 1  
Old 06-22-2011
awk Print get error
Hi, Gurus,
I have script as following:
Code:
#!/usr/bin/khs
lastdate=`cat abc`
echo $lastdate
awk '{ if ($0~/^\$\$lastupdatedate *=/) {print '\$\$lastupdatedate=$lastdate'} else {print $0}}' file1 > tmp

error message
Code:
awk: syntax error near line 1
awk: illegal statement near line 1

when I change $lastdate to '2001-01-01 00:00:00', code as following:
Code:
#!/usr/bin/khs
lastdate=`cat abc`
echo $lastdate
awk '{ if ($0~/^\$\$lastupdatedate *=/) {print "$$lastupdatedate=2001-01-01 00:00:00"} else {print $0}}' file1 > tmp

Smilie

Any body can help me out

Thanks in advance
ken002
# 2  
Old 06-22-2011
That's a useless use of backticks. Why do "var=`cat stuff` ; echo $var" when just "cat stuff" achieves the same thing?

It's valid in my awk. Depending on your system, 'awk' may actually be an ancient feature-deprived version, try nawk.

I'm not sure it's actually doing what you want either, though. That $$ may be turning into a number, the shell's PID.

There's an easier and safer way to get variables into awk/nawk than fooling with single/double quotes:

Code:
echo asdf | awk -v var="qwerty" '{ print $1, var }'

---------- Post updated at 01:23 PM ---------- Previous update was at 01:15 PM ----------

Or even get the var in awk itself:
Code:
awk 'BEGIN { getline var <"abc" } { print $0, var }'

Last edited by Corona688; 06-22-2011 at 04:26 PM.. Reason: fix typos, sorry
This User Gave Thanks to Corona688 For This Post:
# 3  
Old 06-22-2011
Also, you probably should fix your shebang line:
Code:
#!/usr/bin/ksh


# 4  
Old 06-22-2011
Thanks both of you.
My situation is:
In my first file abc contains one string '2011-01-01' (only on line), in my second file contains multiple lines, one of them is $$lastupdatedate=xxxx-xx-xx, I want replace xxxx-xx-xx with 2011-01-01 in second file and get $$lastupdatedate=2011-01-01.

Any body can help me out.

Thanks in advance
ken002
# 5  
Old 06-22-2011
Code:
#!/bin/ksh

dateFile=~/test/date.txt
fileToReplace=~/test/input.txt

awk -F= '/^\$\$lastupdatedate/ {$2="'`cat $dateFile`'"}1' OFS="=" $fileToReplace

the regex will match a line starting with '$$lastupdatedate', and replace the second field (stuff after equal sign) with the contents of $dateFile. '1' at the end is just a shortcut to print everything out.
This User Gave Thanks to mirni For This Post:
# 6  
Old 06-23-2011
Thanks Mirni for your detail explanation.

It works perfectly.

---------- Post updated 06-23-11 at 10:51 AM ---------- Previous update was 06-22-11 at 09:10 PM ----------

Hi, Mirni,
Above scripts works fine when I tried on my laptop. But it give me error when I tested on my workstation.
awk: syntax error near line 1
awk: illegal statement near line 1
the system as following
$ uname -a
SunOS abc 5.10 Generic_144488-11 sun4v sparc SUNW,Sun-Fire-T200

any idea about this?

Thanks in advance
ken002
# 7  
Old 06-23-2011
Use nawk on Solaris.
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