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Help File Copy Historical Files

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# 1  
Old 06-22-2011
Help File Copy Historical Files
Hello,

I have a directory /files/storage in which I have files having file name in format as follows

sabclin.yyyymmdd.0 e.g. sabclin.20110621.0 etc.

I want to copy all files that have a date in their file name i.e. yyyymmdd from today till 300 days in the past to another directory, I need to go by the date in the filename and not by -mtime on the file.

I would really appreciate your help.
# 2  
Old 06-22-2011
Hello,

You can get the date needed using the datecalc script provided in this forum otherwise , if you have oracle installed on your system, connect to it and get the date from there in the format and delete the files with that name.

Regards
Ravi
# 3  
Old 06-22-2011
Hello,

Thanks, but I do not follow. Date calc script? First I guess some how I need to get the date out from the file name isnt it? I am not quite sure how and then some how compare that date with todays date to see if days in between is less than or equal to 300 then copy over the file.

I did not quite understand the oracle part, I would like to accomplish it all in KSH.

Would appreciate any help
# 4  
Old 06-22-2011
Hello,

https://www.unix.com/answers-frequent...rithmetic.html

Gives you the details of how to extract date etc.

here is the snippet of your requirement:


Code:
 
get_JD () {
scale=0
echo " $1-32075+1461*($3+4800+($2-14)/12)/4+367*($2-2-($2-14)/12*12)/12-3*(($3+4900+($2-14)/12)/100)/4 " | bc
}

for file in the file list
do

first=`get_JD 1 1 2011` ## here pass the date extracted from first file
second=`get_JD 1 2 2011` ## here pass the current date
 
## date format passed dd mm yyyy format
 
diff=`expr $second - $first`
 
if [ $diff -ge 300 ]; then
cp $file destination_folder
fi

done

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