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extract whole thing in word, leaving behind last word. - perl

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Top Forums Shell Programming and Scripting extract whole thing in word, leaving behind last word. - perl
# 1  
Old 06-22-2011
Question extract whole thing in word, leaving behind last word. - perl
Hi,

i've a string
/u/user/DTE/T_LOGS/20110622_011532_TEST_11_HD_120/HD/TESi T_11_HD_120/hd-12

i need to get string, like

/u/user/DTE/T_LOGS/20110622_011532_TEST_11_HD_120/HD

the words from HD should get deleted, i need only a string till HD, i dont want to use any built in fuctions, pure reg-x code i need.

like :
/u/user/DTE/T_LOGS/20110622_011532_TEST_11_HD_120/HD


Please help,
Thanks,
asak
# 2  
Old 06-22-2011
Code:
 
bash-3.00$ echo "/u/user/DTE/T_LOGS/20110622_011532_TEST_11_HD_120/HD/TESi T_11_HD_120/hd-12" | sed 's/\/HD\/.*$/\/HD/'
/u/user/DTE/T_LOGS/20110622_011532_TEST_11_HD_120/HD

# 3  
Old 06-22-2011
hi,

can you please explain, what is it doing ?

please..

regards,
asak
# 4  
Old 06-22-2011
we are simply replacing the HD..........(followed by any number of characters) to HD

Code:
sed 's/\/HD\/.*$/\/HD/'

the above sed code looks for the string /HD/ and replace the /HD/.......... to /HD
This User Gave Thanks to itkamaraj For This Post:
asak
# 5  
Old 06-22-2011
Try this
Code:
 
perl -pe 's/(.+HD)\/.*/\1/'

This User Gave Thanks to getmmg For This Post:
asak
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