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How to capture the cause of the exception using unix shell?

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# 1  
Old 06-17-2011
How to capture the cause of the exception using unix shell?
Hi all,

Can u pls guide me in the following requirement,

Am capturing the exceptions and the cause of that exception from a log file.

i cud capture the exceptions by simple grep ie., with the following command

cat logfile | grep "Exceptions"

But i couldn't able to capture the cause of that exception. this cause of the exception line can be identified by a pattern "msg=" which occurs before that "Exceptions" occurence.

The thing is if i put `egrep "Exceptions" | "msg="` then it finds all the occurences of "msg=" which is indeed not necessary. i need only the "msg=" occurence line(along with the exceptions) which is found before the "Exceptions" pattern line.

Thanks in Advance!! Please help on this...
# 2  
Old 06-17-2011
please provide the snippet of your log file, and also point out the expected output.
# 3  
Old 06-17-2011
Thanks for ur response!

Log file will look like,

Code:
06-16 23:55:04,INFO,ids*************************sometext,msg=curl -H "cause of the exception"
06-16 23:55:05,WARN,,,,ids*************************sometext Exception: ids*************************sometext
06-16 23:55:04,INFO,,,,ids*************************sometext
06-16 23:55:04,INFO,ids*************************sometext,msg=curl -H "cause of the exception"
06-16 23:55:05,INFO,,,,ids*************************sometext
06-16 23:55:04,INFO,,,,ids*************************sometext
06-16 23:55:05,WARN,,,,ids*************************sometext Exception: ids*************************sometext
06-16 23:55:05,WARN,,,,ids*************************sometext Exception: ids*************************sometext
06-16 23:55:05,ERROR,,,,ids*************************sometext Exception: ids*************************sometext


output file should be like,

Code:
06-16 23:55:04,INFO,ids*************************sometext,msg=curl -H "cause of the exception"
06-16 23:55:04,WARN,,,,ids*************************sometext Exception: ids*************************sometext
06-16 23:55:04,INFO,ids*************************sometext,msg=curl -H "cause of the exception"
06-16 23:55:05,WARN,,,,ids*************************sometext Exception: ids*************************sometext
06-16 23:55:05,WARN,,,,ids*************************sometext Exception: ids*************************sometext
06-16 23:55:05,ERROR,,,,ids*************************sometext Exception: ids*************************sometext

Last edited by pludi; 06-17-2011 at 09:12 AM..
# 4  
Old 06-17-2011
does this help?
Code:
awk '/msg=/{m=$0} /Exception/{ if (m)print m; print $0; m=0}' yourLog.txt

This User Gave Thanks to sk1418 For This Post:
vidhyaS
# 5  
Old 06-24-2011
Hi Thanks.. this code is working for me!! can u pls explain this code...
# 6  
Old 06-24-2011
if your grep support -A and -B then you can try this.

A - after
B - before

Code:
 
grep -B 1 "Exception" filename

Code:
 
awk '/msg=/{m=$0} /Exception/{ if (m)print m; print $0; m=0}' yourLog.txt

if the line has
Quote:
"msg="
word then
Quote:
/msg=/{m=$0}
is storing the whole line into the variable called
Quote:
m
then we are checking the line has the word
Quote:
"Exception"
and if the line has Exception and if the variable m also not empty then print the line and make the msg variable to zero.
This User Gave Thanks to itkamaraj For This Post:
vidhyaS
# 7  
Old 07-07-2011
Hi Just a quick clarification,

if my exception tracking words may be "ERROR" or "Exception" or "exception".

Then shall i use it like,

Code:
awk '/msg=/{m=$0} /exception|ERROR|Exception/{ if (m)print m; print $0; m=0}' >> out3.xls yourLog.txt

Thanks!
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