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how to get rid of all chars after the last decimal points

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# 1  
Old 06-15-2011
how to get rid of all chars after the last decimal points
Hi All,

Here is my original string: 192.168.2.1.8088. The target string I want: 192.168.2.1, how can I use awk or sed or other command to get rid of .8088 in the string?

Thanks,
Ray
# 2  
Old 06-15-2011
Code:
string="192.168.2.1.8088"
string=${string%.*}

# 3  
Old 06-15-2011
Code:
echo '192.168.2.1.8088' |sed 's/.[^.]*$//'
192.168.2.1

This User Gave Thanks to yinyuemi For This Post:
rluo
# 4  
Old 06-15-2011
yet another way...
Code:
echo "192.168.2.1.8088" | awk -F. '{for(i=1;i<NF;i++) printf("%s%s",$i,i==NF-1?"\n":".")}'

# 5  
Old 06-16-2011
doesn't work....
Quote:
Originally Posted by shamrock
yet another way...
Code:
echo "192.168.2.1.8088" | awk -F. '{for(i=1;i<NF;i++) printf("%s%s",$i,i==NF-1?"\n":".")}'

Code:
# uname -a
SunOS 5.10 Generic_144488-06 sun4u sparc SUNW,Sun-Fire-V240
@:/opt/tools>
# echo "192.168.2.1.8088" | awk -F"." '{for(i=1;i<NF;i++) printf("%s%s",$i,i==NF-1?"\n":".")}'
awk: syntax error near line 1
awk: illegal statement near line 1

Last edited by Franklin52; 06-17-2011 at 04:51 AM.. Reason: Please use code tags
# 6  
Old 06-16-2011
for solaris please use nawk... Smilie

Code:
$ echo "192.168.2.1.8088" | nawk -F. '{for(i=1;i<NF;i++) printf("%s%s",$i,i==NF-1?"\n":".")}'
192.168.2.1

# 7  
Old 06-16-2011
Code:
echo '1.2.3.4.5' | nawk -F. 'sub(FS "[^"FS"]*$", "")'
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