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Shell Programming and Scripting

Time Out condition

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# 1  
Old 06-14-2011
Wrench Time Out condition
Hi All,

I need a shell script for getting the input values within a particular time. say for eg. 60 sec. If the user did not give value with in the time limit,then it should display as time out.




Thanks in advance for your kind help Smilie
Last edited by kalai; 06-14-2011 at 07:22 AM..
# 2  
Old 06-14-2011
UPDATE: itkamaraj 's solution below is much more sensible if you are writing a bash script
[strike]Fork and send a sig alarm after 60 from the child then the trap for the sig alarm is to use the default value/terminate with a request to attend the process in future[/strike]
Last edited by Skrynesaver; 06-14-2011 at 06:59 AM..
# 3  
Old 06-14-2011
Quote:
Originally Posted by Skrynesaver
Fork and send a sig alarm after 60 from the child then the trap for the sig alarm is to use the default value/terminate with a request to attend the process in future
Fork command is new to me..
Could u plz show coding for that..



Thanks in advance for your help
# 4  
Old 06-14-2011
man read

check the -t option
# 5  
Old 06-14-2011
Quote:
Originally Posted by itkamaraj
man read

check the -t option
yet i did not get a clear idea there. Smilie
# 6  
Old 06-14-2011
Its something like below..
Code:
#!/bin/ksh
echo "type something.."
read -t 10 var1 # wait for 10 seconds
if [[ -n $var1 ]]
then
        echo "you have entered: $var1"
else
        echo "time is out"
fi

This User Gave Thanks to michaelrozar17 For This Post:
kalai
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