Command param subst to reg expression


 
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# 1  
Old 12-21-2004
Question Command param subst to reg expression

I want to find out Row which starts with, the user specified details to a script.
In general I know what command to be given.
awk '$0~/^Vi/' BReject

But I need to pass on $1 param of command line at the place of 'Vi'.
I tried with -v subst=$1
awk -v subst=$1 '$0~/^subst/' BReject
But it couldnt work.

Any suggestions, Solution must be restricted to awk.
# 2  
Old 12-21-2004
12345

Last edited by druuna; 05-21-2009 at 10:11 AM..
druuna
# 3  
Old 12-21-2004
Quote:
Originally posted by druuna
I wouldn't know a way of putting a variable into a /^VAR/ construct.
You would if you would read our faqs or at least the one entitled "Passing variables/arguments/parameters to commands".
# 4  
Old 12-21-2004
Data

Druuna

It doesnt work. Requirement is it should start with the given pattern.
Actually I have a fixed width file. So there is no fields within.
Its true I need suitable replacement for var within, /^var/.
# 5  
Old 12-21-2004
It worked with me for , at the place of var, '$1'.

Thanks.
# 6  
Old 12-21-2004
i try some thing like this ......



awk -v subst="bhargav" '{ if(match($0,subst) == 1 ){ print $0 } }' txt.tmp
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