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Shell Programming and Scripting

reverse string matching

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# 1  
Old 06-03-2011
reverse string matching
Guys,

I am trying to find a way to achieve this. I need to print /usr/local/apche/htdocs only from the string /usr/local/apache/htdocs/file.php using the regex. The below did not work. I know a solution with normal cut, I need a way to do this with the awk regex.
Code:
awk '/+[\/]file.php/'

# 2  
Old 06-03-2011
use dirname command
Code:
dirname /usr/local/apache/htdocs/file.php

---------- Post updated at 09:14 AM ---------- Previous update was at 08:51 AM ----------

try these also...

Code:
${PATH}/../..
or
echo ${PATH%/*/*}

This User Gave Thanks to itkamaraj For This Post:
anilcliff
# 3  
Old 06-03-2011
Thank you for your reply. However, is there a way for reverse matching using regex, as I mentioned. As I have got forward match working properly.

say, to get using reverse regexp match.
aaa_bbb_ccc
from
aaa_bbb_ccc_ddd
# 4  
Old 06-03-2011
ugly trick

Code:
echo "abc_bbb_ccc_ddd" | awk -F"\_" '{ for (i=1; i<=NF-1; i++) printf ("%s_",$i)}'

# 5  
Old 06-03-2011
How about this?
Code:
echo 'aaa_bbb_ccc_ddd' | awk -F"_" '{$NF=""}1' OFS="_" | sed 's/_$//'

# 6  
Old 06-03-2011
Quote:
Originally Posted by anilcliff
I need to print /usr/local/apche/htdocs only from the string /usr/local/apache/htdocs/file.php using the regex.
Code:
$ echo /usr/local/apache/htdocs/file.php | awk '{sub(/\/[^\/]*$/, ""); print}'
/usr/local/apache/htdocs

Regards,
Alister
# 7  
Old 06-03-2011
Through sed..
Code:
 
echo '/usr/local/apache/htdocs/file.php' | sed 's:/[^/]*$::'

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