Hi everyone,
I am required to mask off the date data for 3 kinds of files. Please help me to find a most generic way to handle the files. Example of the content of each kind(the dates are in red):
1. (1-line files). Possible solution: Date needed to be masked off start with DTM+, end with :203
2.(line by line files). Possible solution: Date needed to be masked off in position 5 to 12 of each line
Code:
EXIT201103281044IAAU 3680272 4363400018000DD FIL IL LEA PERDANA 006 006 MANLEE FD LD RD DD N
DISC201103281101TCKU 9672645 45G1400022500DD FIL RC VIRO BHUM S079 S079 0300312TCNTXG NN N
3.(1 line). Possible solution: Break the line for every 400 character , find the line starting with HHDR, then mask the date from position 14-21
Code:
HHDR 01010020110208000004NYK VERANICD 266 2011020704100020110207181500 D NYKU 5629211 F22521 NY NY N N NZLYT NZZ063854 4510LCI C HHDR 01010020110208000004ARUNIRICKMER 008W 2011020717050020110208010000
Comparing to my solutions above, anyone have a more generic way to handle these 3 kind of files?
Thanks for any effort.
---------- Post updated at 10:48 AM ---------- Previous update was at 10:43 AM ----------
E.g Code to mask off the date(for file 1): nawk'{gsub(/DTM\+7[^>]*'"'"'203/, "DTM+7:201'"'"'203")}'
We have the data looks like below in a log file.
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Source:
#ext1#test1.tale2 drop
#ext1#test11.tale21 drop
#ext1#test123.tale21 drop
#ext2#test1.tale21 drop
#ext2#test12.tale21 drop
#ext3#test11.tale21 drop... (5 Replies)
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File 1 (all contents in 1 line):
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