parsing path


 
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# 1  
Old 05-25-2011
parsing path

Can somebody show me a sed or awk command that can parse a pathname

My input will look like this

/u01/app/oracle/diag/rdbms/ifddb1/ifddb1


I would like my output to get rid of everything including the "/" before
diag. So my output will be this diag/rdbms/ifddb1/ifddb1


I need this to be generic as /u01/app/oracle will always not proceed
what I want.

Thanks to all who answer
# 2  
Old 05-25-2011
Code:
echo '/u01/app/oracle/diag/rdbms/ifddb1/ifddb1' | sed 's#.*/diag/#diag/#'

This User Gave Thanks to vgersh99 For This Post:
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