the smallest number from 90% of highest numbers from all numbers in file


 
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# 8  
Old 05-22-2011
Quote:
Originally Posted by Perderabo
The OP does not know what the limits are... he or she needs to find them. Consider:
Code:
1 2 3 4 7 8 9
1 2 3 6 7 8 9

Now find the middle point. It the first list 4 is the mid point. But in the second list its 6. You don't know 4 or 6 ahead of time. The mid point is the 50% point. Now image a much longer list and you need to find the data element at 10%, 20%, 30%...90% points in the list.
I hope it is reply to ananthap's post, cause if it is directed for me, then I completely don't get it Smilie
# 9  
Old 05-22-2011
Quote:
Originally Posted by bartus11
I hope it is reply to ananthap's post, cause if it is directed for me, then I completely don't get it Smilie
I apologise, bartus11. I'm just learning perl and I did not realise how close yours comes to being correct. Running it though, it does seem to need a little work.

Code:
$ ./sc nums
100% of numbers is bigger than 0.04942771
80% of numbers is bigger than 1.15580244
60% of numbers is bigger than 1.22634608
40% of numbers is bigger than 1.42818227
20% of numbers is bigger than 3.07701713
$
$
$
$
$ grep 0.04942771 nums
0.31556582 0.36677924 0.04942771 1.15580244 1.02877668
$

100% of the numbers are larger than 0.04942771; however one of the numbers is 0.04942771. I have to say that raises a flag. Smilie Maybe you have an off by 1 situation?
# 10  
Old 05-22-2011
Well, maybe I should explain how I understood OP request: get all the numbers into one big set, and in this set find numbers from which 100%, 80%, etc of remaining numbers are greater. So it is not calculating the percentages by lines. It reads all of the number in all of the lines first, and then does the calculation.
# 11  
Old 05-22-2011
I think the OP is after calculating the percentiles.
# 12  
Old 05-22-2011
The OP did say 1000 numbers. Anyway wc or $NR in awk will give the count in the file..

Last edited by ananthap; 05-23-2011 at 04:44 AM..
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