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Shell Programming and Scripting

Finding change in values

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# 1  
Old 05-19-2011
Finding change in values
I have an array

Code:
X = ( -100 -90 -80 -70 -60 -50 -40 30 40 50 60 70 80 90 100 )

I want to find the place where values change from negative to positive.
# 2  
Old 05-19-2011
Which programming language are you using?
# 3  
Old 05-19-2011
awk should be ok
# 4  
Old 05-19-2011
Code:
echo '-100 -90 -80 -70 -60 -50 -40 30 40 50 60 70 80 90 100' | nawk '{for(i=1;i++<NF;) if($i*$(i+1)<0) {print i+1;next}}'

# 5  
Old 05-19-2011
In case multiple changes should be handled:

Code:
awk 'BEGIN {
  n = split("-100 -90 -80 -70 -60 -50 -40 30 40 50 60 70 80 90 100", x)
  for (i = 0; ++i <= n;) {
    if (i > 1) 
      (x[i] > 0) == l || r = r ? r FS i : i
    l = x[i] > 0 
    }
  print "+/- changes in position(s):", r    
  }'

For example:

Code:
% awk 'BEGIN {
  n = split("100 -90 -80 -70 -60 -50 -40 30 40 -50 60 70 80 90 100", x)
  for (i = 0; ++i <= n;) {
     if (i > 1) 
      (x[i] > 0) == l || r = r ? r FS i : i
    l = x[i] > 0
   }
  print "+/- changes in position(s):", r
  }'
+/- changes in position(s): 2 8 10 11

# 6  
Old 05-19-2011
yep, good idea:
Code:
echo '-100 -90 -80 4 5 6 -70 -60 -50 -40 30 40 50 60 70 80 90 100' | nawk '{l="";for(i=1;i++<NF;) if($i*$(i+1)<0) {l=l FS i+1} print "+/- changes in position(s):" l}'

# 7  
Old 05-19-2011
Quote:
Originally Posted by vgersh99
yep, good idea:
Code:
echo '-100 -90 -80 4 5 6 -70 -60 -50 -40 30 40 50 60 70 80 90 100' | nawk '{l="";for(i=1;i++<NF;) if($i*$(i+1)<0) {l=l FS i+1} print "+/- changes in position(s):" l}'

Does this code work if the first element is 100 and not -100?
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