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New Unix user with shell script question using grep

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# 1  
Old 05-18-2011
New Unix user with shell script question using grep
Hello,
I am a new Unix user and new to shell programming. I am working on a script to go through a log file and find the text error:
grep -i 'error' monplus.mplog
if I find the text error in the log file I would like to echo a message to the operator staing there is an error
I am currently using:
Code:
grep -i 'error' monplus.mplog || echo "no errors in file"

which is working fine
I would like to use a loop
Code:
if grep -i 'error' monplus.mplog
then
  echo "There is an error in the monplus.mplog file"
  echo "Please investigate"
else
  echo "There are no errors in the monplus.mplog file"
  exit 1
endif

which is not working and giving a syntax error

Any help would be appreciated...
Thank you...
...Dave
Last edited by Franklin52; 05-19-2011 at 03:30 AM.. Reason: Please use code tags
# 2  
Old 05-18-2011
You almost got it there. You can "and" the result with &&; its usage is pretty much the same as "||"

Code:
grep -iq 'error' monplus.mplog \
&& echo -e "There is an error in the monplus.mplog file\nPlease investigate" \
|| echo "There are no errors in the monplus.mplog file"

# 3  
Old 05-18-2011
One obvious error in the script is endif, shell has fi as end of if statement.
Also, see -q option for grep, it might be handy, as example see below:

Code:
if $(echo "ABCD"|grep -q -i "AB"); then echo OK; else echo NO;fi

would say OK

Code:
if $(echo "ABCD"|grep -q -i "XX"); then echo OK; else echo NO;fi

would say NO
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