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Cut last 13 characters and take the rest of the file name

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# 1  
Old 05-17-2011
Cut last 13 characters and take the rest of the file name
Hi,

I would like to cut last 13 characters of a file name and take the rename the file name as follows:

Input:

A.DAT20110517033732

Output:

A.DAT

I have tried the following command and cut last 13 characters.

Code:
  echo A.DAT20110517033732 | awk '{print substr($0, length($0)-13)}'

But i need A.DAT after i cut the last 13 characters. Please assist me as i am new to shell scripting.

Thanks
Sue
# 2  
Old 05-17-2011
With a posix 'tail'

also :

Code:
echo $a | tail -c 14

Code:
echo $a | sed 's/.*\(.\{13\}\)/\1/'

Code:
t=${a%?????????????}
echo ${a#$t}

Code:
echo $a | cut -c$(echo $(( ${#a}-12 )))-

Code:
$ a=A.DAT20110517033732
$ t=${a%?????????????}
$ echo ${a#$t}
0110517033732
$ echo $a | /usr/xpg4/bin/tail -c 14
0110517033732
$ echo $a | sed 's/.*\(.\{13\}\)/\1/'
0110517033732
$ echo $a | cut -c$(echo $(( ${#a}-12 )))-
0110517033732

Aaaaaa Ooops,

I just realized you do NOT want the 13 last ... Smilie

Ok then just go for:

Code:
echo ${a%?????????????}

or
Code:
echo $a | cut -c1-$(echo $(( ${#a}-13)))

or
Code:
echo $a | sed 's/.\{13\}$//'


Code:
$ a=A.DAT20110517033732
$ t=${a%??????????????}
$ echo $t
A.DAT

Last edited by ctsgnb; 05-17-2011 at 07:58 AM..
# 3  
Old 05-17-2011
you're not a mile off....tweaking your code:

Code:
#  echo A.DAT20110517033732 | awk '{print substr($0,1,length($0)-14)}'
A.DAT

are you wanting to always strip the last 13 chars ? (above is reasonable....many other ways though :-) )

or everything after DAT
Code:
#   echo A.DAT20110517033732 | sed 's/\(.*.DAT\).*/\1/'
A.DAT

or any trailing numerics
Code:
#   echo A.DAT20110517033732 | sed 's/[0-9]*$//'
A.DAT

HTH
# 4  
Old 05-18-2011
Thanks very much guys...Tested all the above and everything worked. You guys are really helpful!
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