Shell Programming and Scripting

Hi,

First off I'm pretty new to scripting so please be gentle.

I am looking for some help with a script that will move all files with a certain extension into a folder within their current location.

Just for clarity I have all my photos organised in directories such as:

/photos/Birthdayparty2009
/photos/Birthdayparty2010
/photos/Christmas2009/Dir1
/photos/Christmas2009/Dir2
/photos/Christmas2010

In each folder I have a jpg version of the photo and a nef (RAW) version.

This can be a problem viewing the photos in slide shows as you get each photo twice and as the RAW files are large it can be quite slow.

So the solution would be the above. Organising the RAW files into a RAW directory for each directory of photos.

The complication is that, as you can see above, there are some dirs that have several sub dirs so it needs to do it recursively.

Anyway down to business:

If been trying to use find / -execdir to do the above but as it is recursive is seems to move the RAW files in the dir into a the RAW dir but then go into the RAW dir and mv the ones its just moved there to a RAW file.

So if I run -

find ./ -name *.nef -execdir mv {} ./RAW \;

on the below dir structure:

.
|-- dir1
| |-- dir3
| | |-- photo1.jpg
| | |-- photo1.nef
| | |-- photo2.jpg
| | |-- photo2.nef
| | |-- photo3.jpg
| | |-- photo3.nef
| | `-- RAW
| |-- photo1.jpg
| |-- photo1.nef
| |-- photo2.jpg
| |-- photo2.nef
| |-- photo3.jpg
| |-- photo3.nef
| `-- RAW
`-- dir2
|-- photo1.jpg
|-- photo1.nef
|-- photo2.jpg
|-- photo2.nef
|-- photo3.jpg
|-- photo3.nef
`-- RAW


I end up with:

.
|-- dir1
| |-- dir3
| | |-- photo1.jpg
| | |-- photo2.jpg
| | |-- photo3.jpg
| | `-- RAW
| | |-- photo1.nef
| | `-- RAW
| |-- photo1.jpg
| |-- photo2.jpg
| |-- photo3.jpg
| `-- RAW
| |-- photo1.nef
| `-- RAW
`-- dir2
|-- photo1.jpg
|-- photo2.jpg
|-- photo3.jpg
`-- RAW
|-- photo1.nef
`-- RAW


I hope that makes sense.

Any help would be appreciated as I've spent hours trying to figure this out.

Code:

du -a /photos_directory|grep ^// |grep -v "RAW"|while read file
do
dir=`dirname $file`
f=`basename $file`
mkdir -p $dir/RAW
mv $file $dir/RAW/$f
done

Try this code with some dummy directory with few sample files.

The "du -a" part gives me -

0 ./dir2/photo3.jpg
0 ./dir2/photo3.nef
0 ./dir2/photo2.jpg
0 ./dir2/photo1.jpg
0 ./dir2/photo2.nef
4 ./dir2/RAW
0 ./dir2/photo1.nef
8 ./dir2
0 ./dir1/photo3.jpg
0 ./dir1/photo3.nef
0 ./dir1/dir3/photo3.jpg
0 ./dir1/dir3/photo3.nef
0 ./dir1/dir3/photo2.jpg
0 ./dir1/dir3/photo1.jpg
0 ./dir1/dir3/photo2.nef
4 ./dir1/dir3/RAW
0 ./dir1/dir3/photo1.nef
8 ./dir1/dir3
0 ./dir1/photo2.jpg
0 ./dir1/photo1.jpg
0 ./dir1/photo2.nef
4 ./dir1/RAW
0 ./dir1/photo1.nef
16 ./dir1
36 .

So the "grep ^//" returns nothing. Am I missing something from the du command that will return the listing in a different format or is there a way of stripping out the part of the line I don't need.

I've played with sed to strip out the first 2 characters but its not always 2 characters so doesn't work.

Can you try this.

Code:

find /photos/dir -type f|while read file do 
dir=`dirname $file`
f=`basename $file`
if [[ $f =~ $nef ]]
then
    mkdir -p $dir/RAW
    mv $file $dir/RAW/$f
fi
done

Sorted!

The ls didn't quite return the required output either so I went back to find.

A few other small adjustments to your script and its testing fine. I'm just doing a quick backup before I run it on the actual data though.

What I've got now for ref:

#!/bin/sh

find . -type f -print|grep "nef"|while read file
do
dir=`dirname $file`
f=`basename $file`
mkdir -p $dir/RAW
mv $file $dir/RAW/$f
done


Thanks for your help kumaran. Appreciated.