Shell Programming and Scripting

Dear Experts,

I need to extract specific records from one file which has multiline records.

Input file pattern is:

============
aaaaaaaa
bbbbbbbb
asdf 1234
cccccccc
dddddddd

============
aaaaaaaa
bbbbbbbb
qwer 2345
cccccccc
dddddddd

============
qqqqqqqq
rrrrrrrrrrrrr
asdf 1234
cccccccc
dddddddd

============

In output I only want records which have "asdf 1234" as pattern:

============
aaaaaaaa
bbbbbbbb
asdf 1234
cccccccc
dddddddd

============
qqqqqqqq
rrrrrrrrrrrrr
asdf 1234
cccccccc
dddddddd

============

Pls suggest how this can be done.

Thanks,
Dhiraj

Do you want 2 lines above and below the pattern?
Requirement is not very clear.

regards,
Ahamed

Hi,

I want entire record which is delimited by "===========" pattern.
Record can be of variable size (i.e lines count can change).
But it will start & end with "=============".

============
aaaaaaaa
bbbbbbbb
asdf 1234
cccccccc
dddddddd
asdsdsaff

============




Thanks,
Dhiraj

Try

Code:

cat input | tr "\n" " " | tr "=" "\n" | awk '/asdf 1234/ { printf $0 } ' | tr " " "\n"

Try this

Code:

awk '/^=/{if(s==1){s=0}else{s=1}}{x[++i]=$0}/asdf 1234/{f=1};{if(f==1&&s==0){for(j=0;j<i;j++){if(x[j]){print x[j]}}i=0;}}' file

regards,
Ahamed

Sorry for my post above, i belive this code should work much better

Code:

awk '{ RS="============" } /asdf 1234/ { print $0  } ' input  ## or printf $0RS"\n"

Nice one!
I though "=====" may not be constant.

regards,
Ahamed