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difference between sh filename.sh and . filename

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# 1  
Old 05-05-2011
difference between sh filename.sh and . filename
Hi, Gurus,
I feel sorry to ask this easy question, but to be honest, I really don't know.
I have a question about execute shell script.
I have script named as filename.sh with -rwxr-xr-x permission.
when I execute it with
Code:
. filename.sh

It works properly.
when I exec it with
Code:
sh filename.sh

It does not work.
SmilieSmilie

Any idea about this.

Thanks in advance
ken002
# 2  
Old 05-05-2011
Quote:
"It does not work"
If you tried, I don't think you could be more vague.

Based on such limited information the best I could suggest is that you didn't export one or more variables from wherever you are trying to run filename.sh from (sh filename.sh - not an issue when you source (with .) filename.sh).

Please try to be more descriptive than saying "It does not work".

Running it "sh ..." will run the script in a new sub-shell (sh - or whatever that point to (bash, ksh, dash, etc.)). Running it with . will source (effectively load) it into the current shell's environment.
This User Gave Thanks to Scott For This Post:
# 3  
Old 05-05-2011
Is this a Bourne or Korn (or whatever script)?
If the first line of your script does not call out a shell, it will run in the shell from which you are logged in as.
Using the . will use the current shell unless overridden by a
Code:
#!/usr/bin/ksh

statement on line #1.
Using sh <script> will force using Bourne shell unless overridden by line #1
# 4  
Old 05-05-2011
Quote:
Originally Posted by Topaz
Is this a Bourne or Korn (or whatever script)?
If the first line of your script does not call out a shell, it will run in the shell from which you are logged in as.
Using the . will use the current shell unless overridden by a
Code:
#!/usr/bin/ksh

statement on line #1.
Using sh <script> will force using Bourne shell unless overridden by line #1
Both methods you suggest render #!/usr/bin/ksh ineffectual.
# 5  
Old 05-05-2011
Quote:
Originally Posted by ken002
Hi, Gurus,
I feel sorry to ask this easy question, but to be honest, I really don't know.
I have a question about execute shell script.
I have script named as filename.sh with -rwxr-xr-x permission.
when I execute it with
Code:
. filename.sh

It works properly.
when I exec it with

. filename.sh executes filename.sh in the current shell.

"When bash is not in posix mode, the current directory is searched if no file is found in PATH."
Quote:
Code:
sh filename.sh

It does not work.

sh will search the directories in $PATH for the file, but it will not search the current directory.
This User Gave Thanks to cfajohnson For This Post:
# 6  
Old 05-05-2011
Thanks everybody,
my default shell
Code:
$ echo $SHELL
/usr/bin/bash

my script exactly same as

Code:
 # --------------------------------------------------------------------------
       #
       # SCRIPT NAME : env.sh
       # DESCRIPTION : set environment variables
       # CREATED     : 23 Nov 2010
       # UPDATED     : 05 Apr 2011
       #  --------------------------------------------------------------------------

ORACLE_SID=abc  
export ORACLE_SID
DB_USR=aaa       
export DB_USR
DB_PASSWD=bbb    
export DB_PASSWD

when I exec sh filename.sh it did not export these variables.

Smilie, Smilie,

Thanks in advance
ken002
# 7  
Old 05-05-2011
Just a detail i want to point out :
Note that with those command
Code:
. filename.sh

and
Code:
sh filename.sh

since filename.sh is an argument, it will be executed even if your filename.sh does not have the +x chmod.

---------- Post updated at 09:49 PM ---------- Previous update was at 09:46 PM ----------

... whereas simply running :
Code:
filename.sh

you may encounter a permission denied if you forgot to set the chmod +x on it
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