Shell Programming and Scripting

Hi,

I have a tab delimited file with 2 columns. In the first column the numbers are sorted from smallest to largest. It is supposed to be in the numerical order but in between some numbers are missing. Is there a way I could easily get those numbers that are missing and output it a file using awk or sed. I can specify the lowest and the largest number.

Please let me know

Not that great but:

Code:

>cat /tmp/a
1
2
3
5
6
9
10
>cat /tmp/b
1
2
3
4
5
6
7
8
9
10
>grep -v -f /tmp/a /tmp/b
4
7
8

Thanks But there is only one file no 2 files

I know. You'll have to make a second file, including all the numbers from low to high.

Code:

awk -v l=$low -v h=$high '{a[$1]=$1;next} END{for(i=l;i<=h;i++) if(i in a) { ;} else { print i}}' file

Thanks for the reply...but I think its not working properly. The file contains 2 columns and I need the first column only to count. My lowest value was 64 and I got values lower than that and even including 64 itself. I think we are close enough to the solution

Check my new changed code in the last post..If it wont work , paste the i/p and o/p extected ( atleast few rows )

Regards
Ravi