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awk : Remove column1 and last column in a line

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# 1  
Old 05-05-2011
awk : Remove column1 and last column in a line
Hi All,

How to remove col1 and last column in a line. Please suggest some awk stuffs.

Input
Code:
col1 col2 col3 col4
col1 col2 col3 col4 col5 
col1 col2 col3 col4
col1 col2 col3

Output
Code:
Processing col2 col3 ...
Processing col2 col3 col4  ...
Processing col2 col3 ...
Processing col2  ...

Thanks,
Mani Muthu
# 2  
Old 05-05-2011
Code:
awk -F' ' '{printf "processing "; for(i=2;i<NF;i++){ printf "%s ",$i}; print "..."}' file_name

# 3  
Old 05-05-2011
Code:
awk '{NF=NF-1;$1=$1;sub(".*"$2,$2,$0)}1' infile

use nawk instead of awk if running on SunOS / Solaris plateform
# 4  
Old 05-05-2011
thanks for your solutions. How to store the col2 to col n-1 in a variable
# 5  
Old 05-05-2011
What is your final goal ?

Code:
awk '{NF=NF-1;$1=$1;sub(".*"$2,$2,$0);print "Processing",$0}' infile

# 6  
Old 05-05-2011
I am trying to extract .rar format files in solaris.
I am using the a utility to extract the files.
While I am extracting a rar file it shows the below message
Code:
Extracting  folder1/folder 2/file OK

Insist of the above message I want to show the below message
Code:
 
Processing folder1/folder 2/file ...

Suppose a path having some space, then $2 getting the partial path name only.
I want to show the full path name.
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