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Can't print multiple lines inside awk :(

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# 1  
Old 05-03-2011
Can't print multiple lines inside awk :(
Hi Friends,

I have small issue with following code snippet.

I am trying call one function inside awk in which the function inturn will echo few lines. However when i ran script its throwing an error saying "nawk: syntax error at source line 1".

Code:
#!/bin/sh
eval input=$@
 
while read line
do
        dataloader=`echo $line|nawk -F"|" '{print $1}'`
                  Chan=`echo $line|nawk -F"|" '{print $3}'`
                  coll=`echo $line|nawk -F"|" '{print $5}'`
                Datach=`echo $line|nawk -F"|" '{print $7}'`
           HAMconf=`echo $line|nawk -F"|" '{print $9}'`

functiontoAddAMGRforFTE()
{
echo  "hai"
echo  "hai2"
}

export var3="FTE."$Chan"."$coll".WORK_LIMIT=100"
nawk -v variable="$var3" '{if($0~/variable/) {print "already exist with configuration for " } else {print "'""`"functiontoAddAMGRforFTE"`""'"}}' $input
done < conffile.txt

# 2  
Old 05-03-2011
Code:
if($0~variable)

And what's the meaning of this:
Code:
{print "'""\`"functiontoAddAMGRforFTE"\`""'"}

# 3  
Old 05-05-2011
Hi,

Thanks for the reply...I have got answer for my question..

I did mistake in writing function(system - shell) which i am trying to call from AWK , hence it was throwing an error with multiple line print statement, instead i modified the script such that to call awk function inside awk script itself and it worked.

Thanks Again
SHa
# 4  
Old 05-05-2011
Code:
...
set -- $(echo $line | sed 's/|/ /g')
dataloader=$1
Chan=$3
coll=$5
Datach=$7
HAMconf=$9
...

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