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Shell Programming and Scripting

Need to validate that all 24 hr are in a table

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Top Forums Shell Programming and Scripting Need to validate that all 24 hr are in a table
# 8  
Old 05-02-2011
Quote:
Originally Posted by paulyester
Code:
$ awk -F: -f awktest3 testhrfile.txtawk: syntax error at source line 15 source file awktest3
 context is
     >>> /^[0-9]/{ <<< 
awk: illegal statement at source line 15 source file awktest3
awk: illegal statement at source line 15 source file awktest3

try:
Code:
#! /bin/awk
{
NR>1
{
if($1-var1==1)
{
var2=$1
}
else
{while (var2<$1-1) 
print ++var2":00"}
}
{if(/^[0-9]/)
var1=$1}
}1

# 9  
Old 05-02-2011
Awesome. Now I'll get out the books and figure out why.

Thanks!
# 10  
Old 05-02-2011
yinyuemi's code has double 6:00 and 15:00.

Here is my solution.

Code:
awk '/Hourly/ {d++;c[d]=$0;next} {a[$1 FS d]=$0}
     END {for (i=1;i<=d;i++) 
             { print c[i]; 
               for (j=0;j<=23;j++) print (a[j ":00" FS i]=="")?j ":00":a[j ":00" FS i]
             }
         }' testhrfile.txt

# 11  
Old 05-02-2011
Thanks for your replySmilie
I have modified the code
Code:
#! /bin/awk
{NR>1
{
if($1-var1==1)
{var2=$1}
else
{while (var2<$1-1) 
print ++var2":00"}
var2=$1}
{if(/^[0-9]/)
var1=$1}
}1

# 12  
Old 05-02-2011
yinyuemi, I have to say your idea is wrong from the beginning.

If the record has no 0:00 or 23:00, how it can be generated by your script.
# 13  
Old 05-02-2011
Quote:
Originally Posted by rdcwayx
yinyuemi, I have to say your idea is wrong from the beginning.

If the record has no 0:00 or 23:00, how it can be generated by your script.

Hi rdcwayx,
your comments is correct, that's the limitation of my script, it's not robust enough, your code is much better.
Aagin, thanks for your correction.
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