Shell Programming and Scripting

Hello Experts

I am newbie to unix and writing one script to make archive files

Problme i am facing is : I have used find command to find the type of files and I am storing find command results in a variable.

When I echo the variable I can see that path is printed properly but when i am making non-enpty or null check on variable it find variable as empty.

var=find . -name ...etc

echo $var ...prints properly but

if(! -z var) (ignores if and goes to else ...it means to me is that variable is empty)

can you please tell how to check if the variable is not null or contain string.

thanks for looking into it.

I really doubt that.

What shell are you using?

thank corona for reply, how do i check shell i am using ..not aware

but good thing is my issue resolved

i did

"var" == "" ( this works for me)

thanks for your help

If you don't even know your shell, your odds of finding a useful answer are pretty small. You may know that == worked but you don't know where or why.

echo $SHELL

Thanks corona, i did and found i am using

/bin/ksh

Okay. So to store the value of something you can do var=$(echo hello)

and an if-statement works like

Code:

if [ -z "$VAR" ]
then
        echo "$var is blank"
        exit 1
fi