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Find Word within ^A delimiter

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# 1  
Old 04-23-2011
Question Find Word within ^A delimiter
I have a file in which the following pattern is there
TAG001^A<value>^A

I want to find all such values(words) which comes right next to "TAG001^A" and before the next "^A".

^A is the delimiter here.

Please help!

Note: I think ^A in unix resolves to \001 as delimiter
Last edited by royzlife; 04-23-2011 at 03:13 PM..
# 2  
Old 04-23-2011
Does the value come in "<" and ">"?
regards,
Ahamed

---------- Post updated at 11:07 AM ---------- Previous update was at 11:05 AM ----------

try this

Code:
echo "TAG001^A<value>^A" | awk -F'\\^A' '{print $2}'

Code:
awk -F'\\^A' /TAG001/ '{print $2}' file

regards,
Ahamed
Last edited by ahamed101; 04-23-2011 at 05:32 PM..
# 3  
Old 04-23-2011
Code:
awk -F"\x01" '$1=="TAG001"{print $2}' file

# 4  
Old 04-24-2011
Code:
echo "TAG001^A<value>^A" | awk -F"<|>" '{print $2}'

# 5  
Old 04-24-2011
I think the question should be re-modified -

in a file we have the following lines -
xxxx^Ayyyy^Azzzz^ATAG001^A12345^ATAG002........
qqqq^Awwww^Aeeee^ATAG001^A56789^ATAG002........

The position of TAG001 is not fixed but per line there is only 1 TAG001.

I need to retrieve the values 12345,56789 which lies within TAG001^A and the next ^A.

I hope the problem is clear than before.

Thanks every one!
# 6  
Old 04-24-2011
Code:
awk -F"\x01" '{for(i=1;i<NF;i++) if($i=="TAG001")print $(i+1)}' file

# 7  
Old 04-24-2011
Code:
$ awk -F'TAG001\\^A|\\^A' '{print $5}' test_file 
12345
56789

$ cat test_file 
xxxx^Ayyyy^Azzzz^ATAG001^A12345^ATAG002........
qqqq^Awwww^Aeeee^ATAG001^A56789^ATAG002........
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