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Shell Programming and Scripting

Replacing strings

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# 1  
Old 04-20-2011
Replacing strings
The code below gives the string "test1.txt" even though "tessdsdt" does not match "test1.txt". I would like to return "" if there is no match and return some kind of error that I can capture and decide what to do.

Code:
echo test1.txt | awk -v src="tessdsdt" -v dst="test" '{sub(src,dst); print}'

# 2  
Old 04-21-2011
Code:
echo test1.txt | 
awk -v src="tessdsdt" -v dst="test" '{if(sub(src,dst)){print} else {print "No match"}}'

# 3  
Old 04-21-2011
I also have another problem. I want to check if $f contains $fsrc, but $match is empty.

Code:
set f = "test1.txt"
set fsrc = "test"
set match = `echo $f | awk '/$fsrc/'`
echo $match

# 4  
Old 04-21-2011
Try this

Code:
#!/bin/ksh

f="test1.txt"
fsrc="test"
match=`grep $fsrc $f`
echo $match

you should use -v and pass arguments to awk if you are using it.

regards,
Ahamed
# 5  
Old 04-21-2011
I have tried the code below to no avail.

Code:
set match = `echo $f | awk -v src=$fsrc '/src/'`

---------- Post updated at 06:04 AM ---------- Previous update was at 05:58 AM ----------

The grep thing is not working.
# 6  
Old 04-21-2011
Quote:
Originally Posted by kristinu
The grep thing is not working.
Did you mean ... ?
Code:
match=`echo $f | grep $fsrc`

# 7  
Old 04-21-2011
Quote:
Originally Posted by kristinu
I have tried the code below to no avail.

Code:
set match = `echo $f | awk -v src=$fsrc '/src/'`

---------- Post updated at 06:04 AM ---------- Previous update was at 05:58 AM ----------

The grep thing is not working.
You sure you have the string "test" in the file "test1.txt?

regards,
Ahamed
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