Shell Programming and Scripting

var1=`echo "emp,dept,salgrade" | awk -F, '{print NF}'`
count=1
while [ $count -le $var1 ];
do
i=`expr $count`
tname[$count]=`echo "emp,dept,salgrade" | awk -F, '{ print $(echo $i) }'`
count=$count+1;
echo ${tname[$count]};
echo $count
done

I want to store in tname[1]=emp, tname[2]=dept,tname[3]=salgrade

I am getting error at line

tname[$count]=`echo "emp,dept,salgrade" | awk -F, '{ print $(echo $i) }'`

Here everything thru the loop i need print $1 for first time
print $2 second time .....so on

I am getting syntax error if i do print $($count) or print $(expr $count), tell me how to store them in the way i wanted ...

If there is any other way of doing this let me know .............

thanks !

You could use cut to get the column, e.g...

tname[$count]=$(echo "emp,dept,salgrade" | cut -d"," -f $count)


OR you might be able to set the array just using one line - not sure if eval is required or not...

IFS="," set -A tname dummy $(echo "emp,dept,salgrade")

pass variable to awk as follows.
Following should work;

-------------------------------------


#!/usr/bin/ksh

var1=`echo "emp,dept,salgrade" | awk -F, '{print NF}'`
echo $var1

count=1
while [ $count -le $var1 ];
do
t=`echo "emp,dept,salgrade" | awk -F"," '{ print $a }' a=$count`
echo $t
tname[$count]=$t
echo ${tname[$count]}
((count=$count+1))
done

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