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Pivot script

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# 1  
Old 04-18-2011
Pivot script
Hi

Please suggest a script that would do a horizontal pivot , on the fields separated by a semicolon
Below is my input file
Code:
 1|c2|aa
1|c3|dd
1|c4|cc
1|c5|aa
1|c6|ss
1|c7|dd
1|c8|bb
1|c9|jjj
1|c10|kkk
1|c11|fffg
1|c12|nnn;indi;pak;linf;wer
1|c13|lllnk;li;sdfsd;oiuo
1|c14|ppp
1|c15|cccc
1|c16|ddd
1|c17|sss
2|c2|ff
2|c3|xxx
2|c4|gry
2|c5|aa
2|c6|ss
2|c7|dd
2|c8|bb
2|c9|jjj
2|c10|kkk
2|c11|fffg
2|c12|nnn
2|c13|llll
2|c14|ppp;yahoo;jink
2|c15|cccc
2|c16|ddd
2|c17|sss

The desired output would be
Code:
1|c2|aa
1|c3|dd
1|c4|cc
1|c5|aa
1|c6|ss
1|c7|dd
1|c8|bb
1|c9|jjj
1|c10|kkk
1|c11|fffg
1|c12|nnn
1|c12|indi
1|c12|pak
1|c12|linf
1|c12|wer
1|c13|lllnk
1|c13|li
1|c13|sdfsd
1|c13|oiuo
1|c14|ppp
1|c15|cccc
1|c16|ddd
1|c17|sss
2|c2|ff
2|c3|xxx
2|c4|gry
2|c5|aa
2|c6|ss
2|c7|dd
2|c8|bb
2|c9|jjj
2|c10|kkk
2|c11|fffg
2|c12|nnn
2|c13|llll
2|c14|ppp
2|c14|yahoo
2|c14|jink
2|c15|cccc
2|c16|ddd
2|c17|sss

I tried using awk with loop but couldn't get the result .
Code:
nawk 'BEGIN{FS="\\;";OFS="|"} {for(i=3;i<=NF;i+=1) print $i}' pivot2.txt > pivot3.txt

Thanks
Arif
Last edited by mabarif16; 04-18-2011 at 01:22 PM..
# 2  
Old 04-18-2011
Try:
Code:
awk '{n=split($3,a,";");for (i=1;i<=n;i++){print $1"\t"$2"\t"a[i]}}' pivot2.txt

# 3  
Old 04-18-2011
Try this,
Code:
awk '{if(/;/){split($3,a,";");for(i in a) {print $1 FS $2 FS a[i]}} else {print $1 FS $2 FS $3}}' inputfile

# 4  
Old 04-18-2011
Quote:
Originally Posted by bartus11
Try:
Code:
awk '{n=split($3,a,";");for (i=1;i<=n;i++){print $1"\t"$2"\t"a[i]}}' pivot2.txt

You forgot to set FS to '|'. Skimming the data and code, a default FS should render a null $3.

Regards,
Alister

---------- Post updated at 01:13 PM ---------- Previous update was at 01:11 PM ----------

Quote:
Originally Posted by pravin27
Try this,
Code:
awk '{if(/;/){split($3,a,";");for(i in a) {print $1 FS $2 FS a[i]}} else {print $1 FS $2 FS $3}}' inputfile

FS needs to be set appropriately. Also, the "in" operator returns array indices in an unspecified order. They may not be in the same order as they occurred in the data. Depending on the OP's requirements, that could be a problem. Not knowing for certain, Bartus11's deterministic loop is probably safest.

Regards,
Alister
# 5  
Old 04-18-2011
How about:
Code:
awk -F\| '{gsub(";",RS $1 FS $2 FS)}1' file

# 6  
Old 04-18-2011
Thank you all for the responses ,
I tried the following , an it provides the required output .
Code:
awk 'BEGIN {FS="|"} {n=split($3,a,";");for (i=1;i<=n;i++) { print n FS $1 FS $2 FS a[i] } }' pivot2.txt

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